Decision statement in Java.<\/li>\n<\/ul>\nWhat is an Armstrong Number in Java?<\/h2>\n
In Java, a number is said to be an Armstrong number if the sum of its own digits raised to a power of digits results in the number itself. For instance, the Armstrong numbers 0, 1, 153, 370, 371, 407, 1634, 8208, and 9474 are both three- and four-digit Armstrong numbers. They are numerous. Consider the number 407, which may be stated as follows because it has three digits:<\/p>\n
(407) \u2014> (4 * 4 * 4) + (0 * 0 * 0) + (7 * 7 * 7)\n 64 + 0 + 343\n => 407<\/code><\/pre>\nAs 407 is a sum of the cube of its digits, therefore it is an Armstrong number.<\/p>\n
Implementation of Armstrong Number Program in Java<\/h2>\n
First, we have to declare the class AmstrongNum.Then declare the variables. Create an object of the scanner class as sc and read the number from the user into the variable num. Assign originalNum=num. Find the sum of cubes of digits of num by using a while loop with condition num != 0,<\/p>\n
\n- Take each digit by finding the remainder of num divided by 10, digit=num<\/li>\n
- Find the cube of the digit using the pow() method of Java, add it with cube_sum<\/li>\n
- To find the next digit we\u2019ll assign the num variable = num\/10.<\/li>\n<\/ul>\n
After exiting from the loop, check if cube_sum is the same as originalNum, if yes then display the number is Armstrong number, else display the number as not Armstrong number using the system.out.println().<\/p>\n
Algorithm of Armstrong Number Program<\/h3>\n\n- Declare the class ArmstrongNum with a public modifier.<\/li>\n
- To start the program open the main(), Java program execution starts with the main()<\/li>\n
- Declare the integer variables originalNum, digit, cubeSum, num<\/li>\n
- Assign cubeSum = 0<\/li>\n
- Create an object of the scanner class<\/li>\n
- Read the number into the variable num<\/li>\n
- Assign originalNum=num<\/li>\n
- By using a while loop with the condition originalNum !=0, do steps 9,10<\/li>\n
- Find the digit, the cube of that digit, and the sum of cubes into cubeSum<\/li>\n
- Then to find the next digit divide the num by 10<\/li>\n
- After processing the loop, check if cubeSum is equal to originalNum\n
\n- if true then display the number as Armstrong number<\/li>\n
- else display the number is not Armstrong.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\t\t\t\t\t\t
![\"\"](\"https:\/\/prepbytes-misc-images.s3.ap-south-1.amazonaws.com\/assets\/1661855824042-Article%20%281%29.jpg\")
<\/p>\n