{"id":14348,"date":"2023-03-14T10:03:44","date_gmt":"2023-03-14T10:03:44","guid":{"rendered":"https:\/\/www.prepbytes.com\/blog\/?p=14348"},"modified":"2023-03-14T10:03:44","modified_gmt":"2023-03-14T10:03:44","slug":"strong-numbers","status":"publish","type":"post","link":"https:\/\/prepbytes.com\/blog\/strong-numbers\/","title":{"rendered":"What are Strong Numbers"},"content":{"rendered":"

\"\"<\/p>\n

There are various types of special numbers and series in Mathematics such as Armstrong Numbers, Fibonacci Numbers, Strong Numbers, Palindrome Numbers, etc. Here we will discuss Strong Numbers in detail, Algorithms, and Code for Strong Numbers in Java and Python. So, let\u2019s start.<\/p>\n

Strong Numbers<\/h2>\n

\u201cIn Mathematics, Strong Numbers are defined as the number whose sum of the factorial of digits is equal to the number itself.\u201d The following examples will help you in a clear understanding of the above statement.<\/p>\n

Example 1 of Strong Numbers<\/strong>
\nLet us consider a number, 145.<\/p>\n

Here, n = 145
\nand, the Sum of Factorial of digits is = 1! + 4! + 5!
\n= 1 + 24 + 120
\n= 145<\/p>\n

Since the sum of the factorial of digits of the number is equal to the number. So, 145 is a Strong Number.<\/p>\n

Example 2 of Strong Numbers<\/strong>
\nNow, let another number be 534.<\/p>\n

Here, n = 534
\nand, the Sum of Factorial of digits is = 5! + 3! + 4!
\n= 120 + 6 + 24
\n= 150<\/p>\n

Here, the sum of the factorial of digits of the number (i.e., 150) does not equal to the number (i.e., 534). So, 534 is not a Strong Number.<\/p>\n

Now that you have understood the concept of Strong Numbers well, let\u2019s advance to the different methods of Checking whether the given number is strong or not.<\/p>\n

Method 1: Iterative Solution for Strong Numbers<\/h2>\n

The iterative solution for the identification of Strong Numbers is given below along with a stepwise algorithm and code for Strong Numbers in Python and Java.<\/p>\n

Algorithm: How to Check for Strong Number<\/strong>
\nHere’s the algorithm to check if a number is a strong number:<\/p>\n

Step 1:<\/strong> Take input from the user and store it in a variable num.
\nStep 2:<\/strong> Create three variables: original (to store the original value of num), sum (to store the sum of factorials of digits), and digit (to store the current digit of num).
\nStep 3:<\/strong> Set original equal to num.
\nStep 4:<\/strong> Initialize the sum to 0.
\nStep 5:<\/strong> Use a while loop to iterate through each digit of num:
\na.<\/strong> Get the last digit of num using the modulus operator (%).
\nb.<\/strong> Calculate the factorial of that digit using a for a loop. Multiply each number from 1 to the digit to get the factorial.
\nc.<\/strong> Add the factorial to the sum variable and divide the number by 10 to move to the next digit.
\nStep 6:<\/strong> After the while loop, check if the sum variable is equal to the original variable. If it is, then the number is a strong number. Otherwise, it’s not a strong number.<\/p>\n

Code Implementation for Strong Numbers in Java and Python<\/strong>
\nHere is the code for the above-mentioned algorithm for Checking Strong Numbers in Python and Java.<\/p>\n\t\t\t\t\t\t