{"id":10588,"date":"2022-11-19T08:33:32","date_gmt":"2022-11-19T08:33:32","guid":{"rendered":"https:\/\/www.prepbytes.com\/blog\/?p=10588"},"modified":"2023-07-21T06:18:14","modified_gmt":"2023-07-21T06:18:14","slug":"python-program-to-check-armstrong-number","status":"publish","type":"post","link":"https:\/\/prepbytes.com\/blog\/python-program-to-check-armstrong-number\/","title":{"rendered":"Python Program to Check Armstrong Number"},"content":{"rendered":"

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In this blog post, we will explore the concept of the Armstrong Number in Python and learn how to check if a given number is an Armstrong number using Python. We will also provide a Python program that can be used as a foundation for solving related problems. An Armstrong number is a unique kind of number that is equal to the sum of the cubes of its individual digits. For example, numbers like 0, 1, 153, and 370 are considered Armstrong numbers in Python. So, let’s delve into the details and examine the Python program for verifying an Armstrong number.<\/p>\n

What is Armstrong Number in python?<\/h2>\n

A positive integer will be known as an Armstrong number in python of order n if<\/p>\n

abcd… = an + b<\/strong>n + cn + d<\/strong>n + …
\nIn case of an Armstrong number of 3 digits, the sum of cubes of each digit must be equal to the number itself. For example:<\/p>\n

371 = 33<\/em>3 + 77<\/em>7 + 11<\/em>1 = 27 + 343 + 1 \/\/ 153 is an Armstrong number.<\/p>\n

1. Check Armstrong Number in Python Using While Loop<\/h2>\n
    \n
  1. Given a number num, count the length of the number and store it in a variable n1 and initialize variables sum with a value 0 and temp with a value num.<\/li>\n
  2. Run a while loop with a condition if temp>0 and perform the following operations in it.\n
      \n
    • Initialize cur_dig with value temp%10 i.e. it will be the last digit of the temp number.<\/li>\n
    • Add cur_dig**n1 in sum.<\/li>\n
    • Update the value of temp to temp\/\/10.<\/li>\n<\/ul>\n<\/li>\n
    • At last check if num == sum, if it is True then print \u201cNumber is an Armstrong\u201d else \u201cNumber is not Armstrong\u201d.<\/li>\n<\/ol>\n

      Python Program to check Armstrong Number using while loop<\/h3>\n\t\t\t\t\t\t